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Mathematics ⚡ Grade 6 Surface Area: Unfold the Solid, Add Up the Skin
⚡ Grade 6 · Lesson 14 of 14

Surface Area: Unfold the Solid, Add Up the Skin

Flatten a 3D solid into its net, then add up the area of every flat piece — that total is the surface area.

Grade 6Middle School
Surface Area: Unfold the Solid, Add Up the Skin — illustration
💡
The big idea: Surface area is the total area of the 'skin' covering a solid. The easiest way to see it is to unfold the solid flat — that flattened shape is called a net, and it's made entirely of rectangles and triangles you already know how to measure. Add up the area of every piece in the net, and you have the surface area.
🎯 By the end, you'll be able to
  • Identify the net of a rectangular prism, a triangular prism, and a square pyramid
  • Calculate the surface area of a rectangular prism using SA = 2(lw + lh + wh)
  • Calculate the surface area of a triangular prism by summing its two triangular bases and three rectangular sides
  • Calculate the surface area of a square pyramid by summing its square base and four triangular faces
  • Apply surface area to real-world problems like wrapping paper and painting
📎 You should already know
  • Area of rectangles and triangles
  • Identifying 3D solids and their faces

Flatten the box — surface area is just the skin

Picture breaking down a cardboard shipping box for recycling. You pull the tape, and the box collapses flat into one connected shape made of rectangles. That flat shape is called the box's net. Fold it back along the crease lines and you rebuild the exact same box.

Here's the key idea: the amount of cardboard in that flat net is exactly the same as the amount of cardboard covering the 3D box. So instead of imagining a tricky 3D surface, you just add up the area of every flat piece in the net. That total is the surface area — literally the area of the solid's outer skin.

🔑 What is a net?

A net is the two-dimensional shape you get by unfolding a three-dimensional solid so every face lies flat, with no overlaps and no gaps. Nets of the solids in this lesson are built entirely from two shapes you already know how to measure: rectangles and triangles.

Different solids unfold into different nets — but the rule for finding surface area never changes: surface area = sum of the areas of every piece in the net.

Net of a rectangular prism — six rectangles in three matching pairs

Unfold a rectangular prism (a box) with length l, width w, and height h, and you get 6 rectangles — but they come in 3 congruent pairs, because opposite faces of a box are always identical:

  • Top and bottom: two l × w rectangles
  • Front and back: two l × h rectangles
  • Left and right: two w × h rectangles

Add up the three pairs and you get the surface area formula:

SA = 2(lw + lh + wh)

🎮 Rectangular Prism — Label the Faces LIVE
Drag the length, width, and height sliders and watch the labeled prism change shape. Each pair of opposite faces (top/bottom, front/back, left/right) is congruent — that's exactly the pairing you unfold into a net and add up for surface area.
✨ Two ways to compute — same answer

Face-by-face (matches the net directly): find the area of each of the 6 rectangles in the net and add them all up.

Formula shortcut: compute the three different face areas once — lw, lh, wh — add them, then double the sum: 2(lw + lh + wh). This works because each face area appears exactly twice in the net (once for each face in its matching pair).

Net of a triangular prism — two triangles, three rectangles

A triangular prism has two identical triangular ends (the bases) connected by three rectangular sides — one rectangle per edge of the triangle. Unfolded, the net shows the two triangles plus three rectangles laid flat, each rectangle's width matching one side of the triangle and its length matching the prism's length.

SA = 2 × (area of triangular base) + (perimeter of triangle) × (prism length)

The perimeter × length term is really just the three rectangles added together in one step, since their combined width is the triangle's perimeter.

Net of a square pyramid — one square, four triangles

A square pyramid has one square base and four triangular faces meeting at the apex. Unfold it and the net looks like a square with a triangle flapped open on each of its four sides — like a pinwheel or a paper crown.

Each triangular face has a base equal to the side of the square, s, and a height called the slant height, l (measured along the face, from the middle of a base edge up to the apex — not the same as the pyramid's straight-up height).

SA = s² + 4 × (½ × s × l) = s² + 2sl

⚠️ Don't mix up surface area with volume

Surface area measures the skin (square units — cm², in², etc.); volume measures the space inside (cubic units — cm³, in³). A box holding more stuff (bigger volume) doesn't automatically need more wrapping paper (surface area) than a different box — the shapes matter, not just the size.

Also watch for missing faces in real problems: an open-top crate or a room being painted (no ceiling painted, say) has fewer faces than the full net — always re-check which faces the problem actually wants.

📝 Worked example: Find the surface area of a rectangular prism with length 5 cm, width 3 cm, and height 4 cm.
  1. Unfold into 3 pairs of rectangles: top/bottom (5×3), front/back (5×4), left/right (3×4).
  2. Area of each pair: 5×3 = 15, 5×4 = 20, 3×4 = 12.
  3. Add the three areas: 15 + 20 + 12 = 47.
  4. Double it, since each face has a matching partner: 2 × 47 = 94.
✓ Surface area = <strong>94 cm²</strong>.
📝 Worked example: A gift box measures 30 cm long, 20 cm wide, and 10 cm tall. How much wrapping paper is needed to cover it exactly (ignoring overlaps and folds)?
  1. This is a real-world surface area problem: wrapping paper covers every face of the net.
  2. Compute the three face areas: lw = 30×20 = 600, lh = 30×10 = 300, wh = 20×10 = 200.
  3. Add them: 600 + 300 + 200 = 1100.
  4. Double it: 2 × 1100 = 2200.
✓ The box needs <strong>2,200 cm²</strong> of wrapping paper.
📝 Worked example: A square pyramid has a base side of 6 units and a slant height of 5 units. Find its surface area.
  1. Base area: s² = 6² = 36.
  2. One triangular face: ½ × s × l = ½ × 6 × 5 = 15.
  3. Four triangular faces: 4 × 15 = 60.
  4. Total: base + four triangles = 36 + 60 = 96.
✓ Surface area = <strong>96 square units</strong>.

Check your understanding

1. When you unfold a rectangular prism into its net, how many rectangles do you get?
A rectangular prism has 6 faces, arranged in 3 congruent pairs (top/bottom, front/back, left/right) — so its net is made of 6 rectangles.
2. Find the surface area of a rectangular prism with length 4, width 2, and height 3.
SA = 2(lw + lh + wh) = 2(4×2 + 4×3 + 2×3) = 2(8 + 12 + 6) = 2(26) = 52.
3. A triangular prism's triangular base has sides 3, 4, and 5 (area 6 square units), and the prism is 10 units long. What is its surface area?
SA = 2 × (triangle area) + (perimeter) × (length) = 2(6) + (3+4+5)(10) = 12 + 120 = 132.
4. A square pyramid has a base side of 4 and a slant height of 6. What is its surface area?
SA = s² + 2sl = 4² + 2(4)(6) = 16 + 48 = 64.
5. You want to know exactly how much paint is needed to cover the outside of a box-shaped shed. Which measurement should you calculate?
Paint covers the outer skin of the solid, which is measured by surface area — the total area of the net's faces, not the space enclosed (volume).
✅ Key takeaways
  • A net is the flat shape you get by unfolding a 3D solid — surface area is just the total area of every piece in that net.
  • A rectangular prism unfolds into 6 rectangles (3 congruent pairs): SA = 2(lw + lh + wh).
  • A triangular prism unfolds into 2 triangles + 3 rectangles: SA = 2 × (triangle area) + (perimeter × length).
  • A square pyramid unfolds into 1 square + 4 triangles: SA = s² + 2sl, using the slant height.
  • Surface area (square units, the skin) is a different quantity from volume (cubic units, the space inside) — don't mix them up.