Instantaneous & Average Power
How power flows in AC circuits — oscillating instant by instant, yet delivering useful energy at a steady average rate.
A light bulb connected to AC glows steadily — yet the power delivered to it reverses direction 120 times per second. How does that work?
Instantaneous power: the product rule
In DC circuits, power is simply P = VI — a constant. In AC circuits, both voltage and current vary with time, so the power delivered at any instant is the product of the instantaneous voltage and instantaneous current:
The instantaneous power p(t) tells you exactly how much energy per second is flowing into the load at moment t. For a resistor, this power is always non-negative (the resistor never returns energy). For reactive elements like capacitors and inductors, p(t) swings positive and negative — energy flows in during part of the cycle and back out during another part.
Expanding p(t) for sinusoidal signals
When voltage and current are sinusoids — v(t) = V_m cos(ωt + θ_v) and i(t) = I_m cos(ωt + θ_i) — we can expand the product using the trigonometric identity cos(A)cos(B) = ½[cos(A−B) + cos(A+B)]. This splits p(t) into two distinct terms with very different physical meanings.
The two terms and what they mean
The constant term, (V_m I_m/2) cos(θ_v − θ_i), represents the net energy per cycle that is converted to heat, light, mechanical work, or otherwise dissipated. This is the real or average power.
The oscillating term, (V_m I_m/2) cos(2ωt + θ_v + θ_i), swings positive and negative at twice the source frequency. Over one complete period T = 2π/ω, the cosine of 2ωt goes through two full cycles, so its integral — and hence its average — is exactly zero. It represents energy sloshing back and forth between source and load without net delivery.
Average (real) power
Because the double-frequency term integrates to zero over one period, the average power is simply the constant term from the expansion:
The phase angle's role
The factor cos(θ_v − θ_i) is called the power factor. It ranges from 0 to 1 and tells you what fraction of the maximum possible power is actually delivered. A purely resistive load has θ_v = θ_i (zero phase difference), giving a power factor of 1. A purely reactive load (ideal capacitor or inductor) has a 90° phase difference, giving a power factor of 0 — no net power is delivered, even though current flows.
- Identify the parameters: Vm = 100 V, Im = 4 A, θv = 20°, θi = −10°.
- Compute the amplitude factor: Vm Im / 2 = (100 × 4) / 2 = 200.
- Compute the phase difference: θv − θi = 20° − (−10°) = 30°.
- Constant term: 200 cos(30°) = 200 × 0.8660 = 173.2 W.
- Double-frequency term: 200 cos(2ωt + θv + θi) = 200 cos(2ωt + 20° + (−10°)) = 200 cos(2ωt + 10°) W.
- Assemble p(t) = 173.2 + 200 cos(2ωt + 10°) W.
- Average power equals the constant term: P = 173.2 W.
- Amplitude factor: Vm Im / 2 = (50 × 2) / 2 = 50.
- Phase difference: θv − θi = 30° − (−30°) = 60°.
- P = 50 cos(60°) = 50 × 0.5 = 25 W.
Check your understanding
- Instantaneous power p(t) = v(t)·i(t) expands into a constant term plus a double-frequency (2ω) oscillating term.
- The constant term (Vm Im / 2) cos(θv − θi) is the average power P — the only part that delivers net energy.
- The oscillating term averages to zero over one period because the integral of cosine over full cycles is zero.
- The power factor cos(θv − θi) ranges from 0 (purely reactive) to 1 (purely resistive), governing how much power is actually delivered.