Current Density, the Continuity Equation & Ohm's Law in Point Form

From lumped circuits to fields: how charge flows steadily through conductors

ElectromagneticsElectrical Engineering Year 2Free preview
⏱️ About 16 min

You already know V=IR from circuit theory. But what happens inside the wire at the level of fields and charges? The answer connects everything you learned about electrostatics to the world of moving charge — and it starts with a single vector field.

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The big idea: Current density J is a vector field that describes charge flow at every point in space. In steady state, charge conservation forces J to be divergence-free, and Ohm's law in point form J=σE ties current density directly to the local electric field inside a conductor.
🎯 By the end, you'll be able to
  • Define current density J as a vector field and relate it to total current I and cross-sectional area A
  • Derive and interpret the continuity equation as a statement of local charge conservation
  • Explain why steady currents require J to be divergence-free and what that means physically
  • Apply Ohm's law in point form J=σE to compute the electric field inside a current-carrying conductor

From Electrostatics to Steady Currents

Having spent two modules on electrostatics — Coulomb's law, Gauss's law, electric potential, conductors, capacitors, dielectrics, and boundary conditions — you have a thorough understanding of what happens when charges sit still. But charges rarely sit still forever. When an electric field exists inside a conductor, free charges move, and that motion is what we call electric current. In this lesson, we take the first step from electrostatics into steady currents, bridging the lumped-element world of circuit theory (V=IR) with the field-theoretic description that will carry us through the rest of this module and into magnetostatics.

Current Density as a Vector Field

The total current I through a surface tells you how much charge crosses that surface per unit time. But I is an aggregate quantity — it tells you nothing about where, or in what direction, the charge is flowing at a specific point. For a field description, we need current density J, a vector field with units of A/m². At any point, J points in the direction of positive charge flow, and its magnitude equals the current per unit cross-sectional area flowing normal to that area.

For uniform current distributed evenly across a flat cross-section of area A, the relationship reduces to a scalar equation. When the flow is non-uniform, you must integrate J over the surface to recover the total current: I = ∫∫J·dS.

\[ \mathbf{J} = \frac{I}{A} \]
Current density for uniform flow through a flat cross-section of area A.

Direction Matters

Because J is a vector field, it can vary in both magnitude and direction from point to point. In a simple round wire carrying DC, J is uniform and points along the wire axis. In a grounded conductor carrying current away from a buried electrode, J fans outward radially and decreases with distance. The vector nature of J becomes essential when we write the continuity equation, which is a statement about how J flows through space.

📝 Worked example: A copper wire has a cross-sectional area A = 2 mm² = 2×10⁻⁶ m² and carries a current I = 5 A. Find the current density J.
  1. Use the uniform-current relation J = I/A.
  2. Substitute: J = 5 A / (2×10⁻⁶ m²).
  3. Compute: J = 2.5×10⁶ A/m² = 2.5 MA/m².
✓ J = 2.5×10⁶ A/m² (2.5 MA/m²)
🔑 Scale Check

The value 2.5 MA/m² is entirely typical for household wiring — copper conductors routinely carry current densities of this order. A 'megaamp per square meter' sounds enormous compared to the 5 A you read on an ammeter, but it reflects how little cross-sectional area a thin wire actually has.

The Continuity Equation

Now we ask a deeper question: can charge pile up or deplete at a point in space? Intuitively, if more current flows into a tiny volume than flows out, the charge density inside that volume must be increasing. The continuity equation makes this precise.

Consider a small closed volume V bounded by surface S. The net current flowing out through S is ∫∫J·dS. By definition, that outflow must reduce the total charge inside: ∫∫J·dS = −d/dt∫∫∫ρdV. Applying the divergence theorem to the left side and noting that the volume is arbitrary, we obtain the differential (point-form) continuity equation.

\[ \nabla \cdot \mathbf{J} = -\frac{\partial \rho}{\partial t} \]
The continuity equation: the divergence of current density equals the negative rate of change of charge density.

Steady Currents Are Divergence-Free

This equation is a local statement of charge conservation. For steady currents — the focus of this module — nothing changes with time. Charge may be moving, but the charge density at every point is constant. That means ∂ρ/∂t = 0, and the continuity equation simplifies to ∇·J = 0.

\[ \nabla \cdot \mathbf{J} = 0 \quad \text{(steady currents)} \]
For steady currents, current density is divergence-free (solenoidal).
✨ KCL Is Just ∇·J = 0

This is the same 'what goes in must come out' principle you intuit from Kirchhoff's current law (KCL) in circuit theory. KCL is just the integral form of ∇·J = 0 applied at a circuit node. The field version holds at every point in space, not just at wire junctions.

Ohm's Law in Point Form

The last piece we need is a relationship between the current density J and the electric field E that drives it. Consider a cylindrical conductor of length L, cross-section A, and conductivity σ. A voltage V applied across its ends produces a uniform field E = V/L inside. The current is I = V/R, and for a uniform conductor R = L/(σA), so I = VσA/L = σEA. Dividing by area gives J = I/A = σE. This is Ohm's law in point form — it holds at every point inside the material, regardless of geometry.

\[ \mathbf{J} = \sigma \mathbf{E} \]
Ohm's law in point form: current density is proportional to the local electric field, with conductivity σ as the constant of proportionality.
✨ Conductivity as a Material Property

Conductivity σ (units S/m) is a material property. Good conductors like copper have σ ≈ 5.8×10⁷ S/m; insulators have σ near zero. The point-form law J = σE works for any field distribution — uniform or non-uniform — as long as the material is ohmic (linear).

✏️ Practice: A copper wire has conductivity σ = 5.8×10⁷ S/m and carries a current density J = 1.16×10⁶ A/m². Find the electric field E inside the wire.
V/m
Solution
  1. Rearrange Ohm's law in point form: E = J/σ.
  2. Substitute: E = (1.16×10⁶) / (5.8×10⁷).
  3. Compute: E = 0.02 V/m.

Why Wires Look Like Equipotentials

The result — E = 0.02 V/m — is astonishingly small. It takes only two hundredths of a volt per meter of electric field to drive 5 A through a copper wire of this cross-section. Copper's enormous conductivity means that even tiny fields produce substantial currents. This is why, in circuit analysis, we often treat wires as equipotential: the field inside is negligible, and so the voltage drop along a short wire is practically zero.

Check your understanding

1. For steady currents, what does the continuity equation reduce to?
Steady currents mean ∂ρ/∂t = 0, so ∇·J = 0 — current density is divergence-free.
2. A conductor carries J = 2×10⁶ A/m² with σ = 1×10⁷ S/m. What is E?
E = J/σ = (2×10⁶)/(1×10⁷) = 0.2 V/m.
✅ Key takeaways
  • Current density J (A/m²) is a vector field giving current per unit cross-sectional area; for uniform flow through a flat area, J = I/A.
  • The continuity equation ∇·J = −∂ρ/∂t expresses local charge conservation: any net outflow of J from a region must deplete the charge density there.
  • For steady currents, ∂ρ/∂t = 0, so ∇·J = 0 — current density is solenoidal, meaning what flows in must flow out with no accumulation.
  • Ohm's law in point form, J = σE, relates current density to the local electric field via conductivity σ, and is the microscopic counterpart of V = IR.
➡️ Now that we understand how steady currents produce electric fields inside conductors, the natural question is: do these moving charges also produce magnetic fields? They do — and the Biot-Savart law is the tool that tells us exactly how.
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