Force on a Moving Charge & on a Current-Carrying Conductor

The Lorentz Magnetic Force and Its Macroscopic Form

ElectromagneticsElectrical Engineering Year 2Free preview
⏱️ About 16 min

In Module 4 you learned to calculate the magnetic fields that steady currents produce. Now we ask the complementary question: what force does a magnetic field exert on the charges and currents that sit inside it?

💡
The big idea: The magnetic force on a moving charge is always perpendicular to its velocity, so it changes direction but never speed — and when millions of charge carriers move together inside a wire, the same force adds up to a measurable push on the entire conductor.
🎯 By the end, you'll be able to
  • Apply the Lorentz magnetic force equation F = qv × B to find the force on a single moving charge
  • Determine the direction of the magnetic force using the right-hand rule
  • Explain why the magnetic force does no work on a charged particle
  • Derive and apply the force on a current-carrying conductor F = IL × B

From Fields to Forces

Welcome to Module 5. In the previous module you spent your time computing the magnetic field B produced by various current distributions using the Biot-Savart law and Ampere's law. You also met the magnetic vector potential A. Throughout all of that work the magnetic field was the output — the thing you solved for. Now we turn the relationship around: given an externally produced B field, what force does it exert on the charges and currents that happen to be moving through it?

This is the bridge between magnetostatics and practically everything electromagnetic that moves — from the beam in a mass spectrometer to the armature in an electric motor. The key player is the Lorentz magnetic force, and it comes in two closely related forms: one for a single moving charge and one for a macroscopic current-carrying wire.

\[ \mathbf{F} = q\,\mathbf{v} \times \mathbf{B} \]
Lorentz magnetic force on a point charge q moving with velocity v through a magnetic field B.

Magnitude and Direction

The magnitude of the magnetic force is F = qvB sinθ, where θ is the angle between the velocity vector v and the magnetic field vector B. Several things are worth noting immediately. First, if the charge is at rest (v=0) there is no magnetic force at all — magnetic fields only act on moving charges. Second, the force is maximum when v and B are perpendicular (θ=90°) and zero when they are parallel (θ=0°). Third, and most importantly, the direction of the force is perpendicular to both v and B, determined by the right-hand rule: point your fingers in the direction of v, curl them toward B, and your thumb points in the direction of F for a positive charge. For a negative charge the force points in the opposite direction.

✨ The Magnetic Force Does No Work

Because F is always perpendicular to v, the dot product F·v = 0 at every instant. Power is P = F·v, so the magnetic force transfers zero energy to the charge. It can change the direction of motion but never the speed. A charge moving in a uniform magnetic field traces a circular (or helical) path at constant kinetic energy.

From a Single Charge to a Wire

A current-carrying wire is nothing more than an enormous number of charge carriers drifting through a conductor. If each carrier feels a force qvd×B, and there are n carriers per unit volume moving with drift velocity vd through a wire of cross-section A and length L, the total force on the wire segment is obtained by summing over all carriers. The product nqvdA is exactly the current I, and the length L gives the direction of current flow. The result is the macroscopic force law:

\[ \mathbf{F} = I\,\mathbf{L} \times \mathbf{B} \]
Magnetic force on a straight wire segment of length L carrying current I in a uniform field B. L points in the direction of conventional current.

Reading the Wire-Force Equation

Here L is a vector whose magnitude is the wire length and whose direction is the direction of conventional current flow. The magnitude is F = BIL sinθ, where θ is now the angle between the wire (current direction) and B. The right-hand rule works the same way. When the wire is perpendicular to the field the force is maximum (F=BIL), and when the wire is parallel to the field the force vanishes. This simple equation is the basis for loudspeakers, railguns, and every galvanometer movement.

📝 Worked example: A charge q = 2 µC moves with velocity v = 1×10⁵ m/s perpendicular to a uniform magnetic field B = 0.5 T. Find the magnitude of the magnetic force on the charge.
  1. Since the velocity is perpendicular to B, the angle θ = 90° and sinθ = 1.
  2. F = qvB sinθ = qvB = (2×10⁻⁶ C)(1×10⁵ m/s)(0.5 T).
  3. F = (2×10⁻⁶)(1×10⁵)(0.5) = 0.1 N.
✓ 0.1 N

Why the Cross Product Matters

It is tempting to memorize just the magnitudes, but the cross-product structure is what makes magnetic forces physically interesting. Because the force is always sideways to the motion, a magnetic field can steer a particle — bending its path into a circle — without ever adding or removing energy. This is why mass spectrometers use magnetic fields to separate ions by charge-to-mass ratio: every ion travels at the same speed (the field does not change it), but ions with different q/m values have different radii of curvature. Similarly, in a wire the sideways force on each carrier is transmitted to the lattice through collisions, producing a net mechanical force on the conductor as a whole.

✏️ Practice: A straight wire segment of length L = 0.4 m carries current I = 5 A, oriented perpendicular to a uniform magnetic field B = 0.3 T. Find the magnitude of the force on the wire.
N
Solution
  1. Since the wire is perpendicular to B, sinθ = 1.
  2. F = BIL = (0.3 T)(5 A)(0.4 m) = 0.6 N.

Check your understanding

1. A charged particle moves parallel to a uniform magnetic field. What is the magnetic force on it?
When v is parallel to B, θ=0° and sinθ=0, so F = qvB sin0° = 0.
2. Why does the magnetic force do no work on a moving charge?
Power delivered is P = F·v. Since F = qv×B is always perpendicular to v, F·v = 0 at every instant, so the magnetic force can never do work.
✅ Key takeaways
  • The magnetic force on a moving charge is F = qv × B, with magnitude qvB sinθ.
  • The force is always perpendicular to both v and B, determined by the right-hand rule.
  • Because F ⊥ v, the magnetic force does no work — it changes direction, not speed.
  • Summing the force on all charge carriers in a wire gives F = IL × B, with magnitude BIL sinθ.
➡️ Now that we know a magnetic field pushes on a straight wire, the natural next question is: what happens when the wire is bent into a loop? The forces on opposite sides of the loop no longer cancel — they produce a torque. That is the subject of the next lesson.
Want to test yourself on this? Try the Electrical Aptitude test →