Angle of Twist & Power Transmission

Predict how far a shaft rotates under load — and connect torque to the horsepower or kilowatts flowing through it.

Mechanics of MaterialsMechanical Engineering Year 1Free preview
⏱️ About 16 min

A car's driveshaft spins at thousands of revolutions per minute, delivering power from the engine to the wheels. Under that load the shaft twists slightly — not enough to see, but enough to matter. If the twist is too large, gears misalign, vibrations grow, and efficiency drops. Engineers predict that twist before the shaft is ever built, using the angle-of-twist formula — and they connect it directly to the power the shaft must carry.

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The big idea: The angle of twist of a prismatic circular shaft is φ = TL/(GJ). For a shaft made of segments with different diameters or materials, the total twist is the sum of the segment twists. In power transmission, torque and rotational speed are linked to power by P = Tω. Converting between rpm and rad/s is a routine but error-prone step that deserves explicit care.
🎯 By the end, you'll be able to
  • Compute the angle of twist of a uniform shaft using φ = TL/(GJ)
  • Sum segment twists for stepped shafts
  • Relate power, torque, and rotational speed using P = Tω
  • Convert correctly between rpm and rad/s

The angle-of-twist formula

Just as axial loading stretches a bar by δ = PL/AE, torsion twists a shaft by an angle φ. The derivation combines the definition of shear strain (γ = ρ dφ/dx) with Hooke's law for shear (τ = Gγ) and the torsion formula (τ = Tρ/J). Integrating along the length gives:

\[ \varphi = \frac{T\,L}{G\,J} \]
Angle of twist (radians) for a prismatic circular shaft. T = torque, L = length, G = shear modulus, J = polar moment of inertia.
🔑 Watch your units — consistency is everything

The product GJ is called the torsional rigidity. It has units of N·m². To get φ in radians, ensure T is in N·m, L is in metres, G is in Pa (N/m²), and J is in m⁴. Mixing millimetres and metres is the most common source of errors in hand calculations. A useful sanity check: for steel shafts of ordinary size, the twist angle is usually small — a few degrees at most.

Stepped shafts

If a shaft changes diameter along its length — a stepped shaft — the torque is the same in every segment (for a single applied torque), but J changes. The total angle of twist is the sum of the twists of each segment:

φ_total = Σ (T_i L_i) / (G_i J_i)

The segment with the smaller diameter dominates the total twist because J scales with the fourth power of diameter. A single narrow section can make an otherwise thick shaft surprisingly flexible in torsion.

A stepped shaft with segment 1 (larger diameter) and segment 2 (smaller diameter) carrying torque T. The total twist is the sum of the twists of each segment. Fixed T L₁, d₁ L₂, d₂ J₁ J₂ φ₁ = T·L₁/(G·J₁) φ₂ = T·L₂/(G·J₂) φ_total = φ₁ + φ₂

A stepped shaft fixed at one end with two segments of different diameters carrying torque T. The total twist equals the sum of the individual segment twists.

In a stepped shaft, each segment contributes its own twist angle. The smaller-diameter segment dominates because J scales with d⁴.

Power, torque, and rotational speed

Power is the rate of doing work. For a rotating shaft, a torque T acting through an angle θ does work W = Tθ. Differentiating with respect to time gives the power:

\[ P = T\,\omega \]
Power (Watts) equals torque (N·m) times angular speed (rad/s).
\[ \omega = \frac{2\pi\,N}{60} \qquad P\,(\text{kW}) = \frac{2\pi\,N\,T}{60\,000} = \frac{T\,(\text{N}\cdot\text{m}) \times N\,(\text{rpm})}{9550} \]
Converting rotational speed N in revolutions per minute (rpm) to angular speed ω in rad/s, and the practical power formula used in engineering.
✨ High speed means lower torque for the same power

For a fixed power, torque is inversely proportional to speed. A high-speed motor delivering 100 kW at 3000 rpm produces roughly half the torque of a low-speed motor delivering the same 100 kW at 1500 rpm. This is why gearboxes exist: they trade speed for torque (or vice versa) while conserving power (minus efficiency losses).

🎮 Interactive: twist angle and power LIVE
Predict first: Set torque to 1.0 kN·m, diameter to 50 mm, and length to 2.0 m. Note the twist angle and power at 1500 rpm. Now double the length — what happens to the twist? What happens if you halve the diameter instead?

Interactive shaft-twist simulator showing twist angle, maximum shear stress, and power at 1500 rpm.

Experiment with how torque, diameter, and length affect twist angle, and read the corresponding power at 1500 rpm.
📝 Worked example: A stepped steel shaft (G = 80 GPa) carries a torque T = 1.0 kN·m. Segment AB is 1.0 m long with diameter 40 mm. Segment BC is 1.0 m long with diameter 60 mm. Find the angle of twist of each segment and the total twist. Also find the power transmitted at 1500 rpm.
  1. J_AB = π/32 × 40⁴ = 2.513 × 10⁵ mm⁴ = 2.513 × 10⁻⁷ m⁴.
  2. J_BC = π/32 × 60⁴ = 1.272 × 10⁶ mm⁴ = 1.272 × 10⁻⁶ m⁴.
  3. φ_AB = (1000)(1.0) / (80×10⁹ × 2.513×10⁻⁷) = 1000 / 20 104 = 0.0497 rad = 2.85°.
  4. φ_BC = (1000)(1.0) / (80×10⁹ × 1.272×10⁻⁶) = 1000 / 101 760 = 0.00983 rad = 0.563°.
  5. φ_total = 0.0497 + 0.00983 = 0.0595 rad = 3.41°.
  6. Power: ω = 2π × 1500 / 60 = 157.1 rad/s. P = 1000 × 157.1 = 157 100 W = 157 kW.
  7. Sanity check: the smaller-diameter segment contributes about 5× more twist than the larger one, consistent with J scaling as d⁴.
✓ φ_AB = 2.85°, φ_BC = 0.563°, φ_total = 3.41°, P = 157 kW at 1500 rpm.
✏️ Practice: A 1.5 m steel shaft (d = 40 mm, G = 80 GPa) carries a torque of 0.8 kN·m. What is the angle of twist, in degrees?
°
Solution
  1. J = π/32 × 40⁴ = 2.513 × 10⁵ mm⁴ = 2.513 × 10⁻⁷ m⁴.
  2. φ = (800)(1.5) / (80×10⁹ × 2.513×10⁻⁷) = 1200 / 20 104 = 0.0597 rad.
  3. φ = 0.0597 × 180/π = 3.42°.
✏️ Practice: A motor delivers 30 kW at 1800 rpm. What is the torque, in N·m?
N·m
Solution
  1. T = 9550 × P(kW) / N(rpm) = 9550 × 30 / 1800 = 159.2 N·m.
  2. Check: ω = 2π × 1800 / 60 = 188.5 rad/s. P = 159.2 × 188.5 = 30 000 W = 30 kW.

Check your understanding

1. The angle of twist of a prismatic shaft is given by:
φ = TL/(GJ) is the fundamental angle-of-twist formula, analogous to δ = PL/(AE) for axial loading.
2. For a stepped shaft with two segments in series, the total angle of twist is:
Twist angles add algebraically for segments in series: φ_total = φ₁ + φ₂ + ...
3. A shaft transmits 100 kW at 2000 rpm. The torque is approximately:
T = 9550 × 100 / 2000 = 477.5 N·m ≈ 478 N·m.
✅ Key takeaways
  • Angle of twist: φ = TL/(GJ) (radians).
  • Stepped shafts: total twist is the sum of segment twists.
  • Power transmission: P = Tω, with ω = 2πN/60 for N in rpm.
  • For the same power, higher speed means lower torque.
➡️ When statics alone cannot determine all the reaction torques — for example, a shaft fixed at both ends — you need a compatibility equation. That is the realm of statically indeterminate torsion.
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