Temperature vs. Heat
Temperature is how fast the particles are jiggling; heat is the energy that flows to speed them up or slow them down.
Two words we use interchangeably — but shouldn't
Picture a spark from a sparkler and a bathtub of lukewarm water. The spark is around 2000°C — hot enough to melt metal — yet it can land on your skin without a burn, because it lasts a fraction of a second and carries a tiny amount of total energy. The bathtub is only 40°C, but there's so much water in it that sitting in it too long could actually be dangerous. Something is different between "how hot" and "how much energy," and that difference is exactly what separates temperature from heat.
Temperature measures the average kinetic energy of the particles in a substance — how fast they're moving, on average. Heat is energy in transit: it's what flows between objects because they're at different temperatures. Temperature is a state, like a reading on a thermometer; heat is a process, energy moving from hot to cold until that process stops.
Why heat flows until it stops
Drop a hot spoon into cool soup and the spoon's fast-moving particles start colliding with the soup's slower particles at the boundary. Each collision tends to transfer energy from the faster particle to the slower one, the same way a fast-moving pool ball transfers energy to a stationary one it strikes. Billions of these collisions per second gradually even out the average particle speeds on both sides. When the average kinetic energy — the temperature — is the same throughout, the net flow of energy stops. That state is called thermal equilibrium, and it's why a thermometer left in a cup of coffee eventually settles at the coffee's temperature, not its own.
- Identify the knowns: \(m = 2\text{ kg}\), \(c = 4186\text{ J/(kg·°C)}\), \(\Delta T = 80 - 20 = 60°C\).
- Apply \(Q = mc\Delta T\): \(Q = 2 \times 4186 \times 60\).
- Multiply step by step: \(2 \times 4186 = 8372\), then \(8372 \times 60 = 502{,}320\) J.
- Both sides are water, so the specific heat c is identical and cancels, leaving \(m_1(T_1 - T_f) = m_2(T_f - T_2)\).
- Plug in numbers: \(0.3(90 - T_f) = 0.7(T_f - 20)\).
- Expand: \(27 - 0.3T_f = 0.7T_f - 14\).
- Solve: \(27 + 14 = 0.7T_f + 0.3T_f \Rightarrow 41 = T_f\).
It's tempting to picture heat as a substance stored inside a hot object, but heat only exists as energy on the move, during a transfer. A cup of tea at 90°C holds far less total thermal energy than a bathtub of water at 40°C, simply because the bathtub has vastly more mass — even though the tea is hotter. Avoid saying an object "has" a certain amount of heat; say it has a temperature, and it releases or absorbs heat when that temperature changes.
Check your understanding
- Temperature measures the average kinetic energy of particles; heat is energy transferred between objects because of a temperature difference.
- Objects at the same temperature can hold very different total amounts of thermal energy depending on their mass.
- Q = mcΔT lets you calculate exactly how much heat is needed to change an object's temperature by a given amount.
- When two objects reach thermal equilibrium, the heat lost by the warmer one equals the heat gained by the cooler one, and net energy flow stops.